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Independent Variable vs. Argument of Function

When Euler introduced modern function notation in 1734, he stated, “If $f(\frac {x}{a} + c)$ denotes any function of $ \frac {x}{a} + c$ …”. His use of parentheses introduced a distinction that we describe today as the distinction between a function’s *independent variable* and a function's *argument*.

A function’s argument is the expression that represents the value that will actually be passed to the function’s definition to get a value of the function. |

So, in $y = f(x)$, *x* is *f*’s independent variable and *x* is *f*’s argument. However, in $y = f(\frac{x}{3} + 5)$, *x* is *f*’s independent variable while $\frac{x}{3} + 5$ is *f*’s argument.

The distinction between independent variable and argument can be very useful. You know that the sine function is periodic with period 2π. This means that sin(*x*) = sin(*x*+2π) for all values of *x.* However, the sine function is periodic with respect to what? The sine function has a period of 2π with respect to its *argument*. The value of sine begins to repeat any time sine’s *argument* varies by 2π, as illustrated below.

x (radians) |
sin(3x) |
sin(3x + 2π) |

0.25 | 0.6816 | 0.6816 |

0.4 | 0.9320 | 0.9320 |

1.7 | 0.9258 | 0.9258 |

Figure 3.14.1 displays the graph of $y = \sin(3x)$. The period of sin(3*x*) with respect to *x* is not 2π. But sine's period __with respect to 3 x__

So sin(3*x*) repeats itself whenever the value of $3x$ varies by $2\pi$. But how much must the value of *x* vary so that the value of $3x$ varies by $2\pi$? The value of $3x$ will vary by $2\pi$ whenever the value of *x* varies by $2/3\pi$:.

$$\mathrm{sin} \left(3\left(x+\frac{2}{3}π \right)\right)=\sin\left(3x+3\left(\frac{2}{3}\pi\right)\right)=\sin\left(3x+2\pi\right)$$

Therefore, the value of $\sin(3x)$ is periodic with respect to *x*, but with a period of $(2/3)\pi$. Whenever the value of *x* varies by $(2/3)\pi$, the value of $3x$ varies by $2\pi$, and therefore the value of $\sin(3x)$ will repeat itself whenever the value of *x* varies by $(2/3)\pi$.

We can express the above reasoning formally. The value of $\sin(ax+b)$ repeats itself whenever $ax+b$ varies by $2\pi$. In other words, if we let $\Delta x$ represent the variation in the value of *x* that results in the value of $ax+b$ varying by $2\pi$, then $a(x+\Delta x)+b=(ax+b)+2\pi$. Solving for $\Delta x$, we get:

$$\begin{align}a(x+\Delta x)+b&=(ax+b)+2\pi\\[1ex] ax+a\Delta x+b&=(ax+b)+2\pi\\[1ex] (ax+b)+a\Delta x&=(ax+b)+2\pi\\[1ex] a\Delta x&=2\pi\\[1ex] \Delta x&=\frac{2\pi}{a}\end{align}$$

Therefore, the period of $\sin(ax+b)$ with respect to *x* is $\dfrac{2π}{a}$.

- The periods of sine and cosine with respect to their arguments is 2π. Use the reasoning illustrated in this section to determine the period of each of the following with respect to
*x*. Explain your reasoning. Check your answers in GC by assigning values to the statements’ parameters. - $\sin\left(\dfrac{x}{a}+b\right)$
- $\cos(mx-b)$
- $\cos(4\sin(2x))$
*Consider when the argument to $\cos()$ repeats itself and take into account that $\cos(-u)=\cos(u)$.* - $2^{\sin(3x)}$
- The animation below illustrates entering an argument for a function so that GC’s display of its graph passes through the given points. Do the same for 2.a-2.e.

Exercises 2.f and 2.g ask you to do the reverse of a-e. They ask you to define the function f so that GC’s graph of $y=f(x)$ passes through the given points. - Download this GC file and complete the assigned task.
- Download this GC file and complete the assigned task.
- Download this GC file and complete the assigned task.
- Download this GC file and complete the assigned task.
- Download this GC file and complete the assigned task.
- Download this GC file and complete the assigned task.
- Download this GC file and complete the assigned task.
- The tangent function has a period of π with respect to its argument. This means that $\tan(x+\pi)=\tan(x)$ for all values of
*x*at which $\tan(x)$ is defined. What is the period of $\tan(ax+b)$? Check your answer in GC.