Section
6.2 Closed Form Rate of Change from Closed Form Accumulation
6.2.1 Deriving Rate of Change Functions in Closed Form
Section 6.1 introduced you to a method for
deriving an approximate rate of change function for an exact accumulation
function given in closed form. The method was to allow an interval of length
h to vary through f’s domain. Each value of the function r
defined as $$r(x)=\frac{f(x+h)f(x)}{h}$$ gives the constant rate of change
of the linear function that passes through the points $(x,f(x))$ and $(x+h,
f(x+h))$ on the graph of f. We spoke of $r_f$, the (unknown) exact
rate of change function for f, in terms of approximations to it by
using very small values of h in the definition of r.
We can do more than examine the definition of r in open form. If we
start with a specific exact accumulation function in closed form, then we
can examine its approximate rate of change function in closed form. Let’s
examine the example of $f(x)=(x+1)^2$ and its approximate rate of change
function r.
For $h≠0$, we have
Equation 6.2.1. Using the definition of r to find the rate of change
function for $f(x)=(x+1)^2$
So, $r(x)=2x+2+h$ for any value of x and any value of $h≠0$.
Therefore, for sufficiently small values of h, $r(x) \doteq 2x+2$
and $r_f$, f’s exact rate of change function, is $r_f(x)=2x+2$.
If this analysis is valid, then the graph of f defined as
$f(x)=(x+1)^2$ should coincide with the graph of g defined as
$g(x) = f(a) + \int_a^x (2t+2)dt$. Check this for yourself using GC.
Reflection 6.2.1: Explain again why you must add $f(a)$ to $\int_a^x
r_f(t)dt$ so that the displayed graph if g coincides with the
displayed graph of $y=f(x)$.
Exercise Set 6.2.1
1. In Equation 6.2.1 we used the specific definition of f to derive
an explicit definition of $r_f$. We simply used algebra and we used the fact
that $h \doteq 0$, where “$h \doteq 0$” means that we are talking about
values of h that are larger than 0 but exceedingly small.
Do the same as in Equation 6.2.1 in each of the following functions. Part
(a) is completed as an example. Check your derivations using GC. If your
derivation is correct, then
 The graph of f should coincide with the graph of
$y=f(a)+\int_a^x r_f(t)dt$ after you substitute your derived formula for
$r_f$ in place of the expression “$r_f(t)$”.
 The graph of $r_f$ should coincide with the
graph of r for suitably small values of h.

$f(x)=$

$r(x)=\dfrac{f(x+h)f(x)}{h}$

Derived $r_f$

Graphs coincide?

a) 
$(x+1)^2$ 
$\dfrac{((x+h)+1)^2(x+1)^2}{h}$ 
$2x+2$ 
Yes 
b) 
$(x1)^3$ 
? 
? 
? 
c) 
$(2x+4)^2$ 
? 
? 
? 
2. Derive exact rate of change functions
$r_f$, $r_g$, and $r_h$ in closed form for the exact accumulation
functions f, g, and h, respectively. Why are all
the rate of change functions the same?
a) $f(x)=x^22x1$
b) $g(x)=x^22x+2$
c) $h(x)=x^22x+7$
6.2.2 Holy cow! A connection!
Here’s a thought you should have: In Chapter 5, we derived exact
accumulation functions in open form from exact rate of change functions in
closed form. We started with exact rate of change functions like $r(x)=2x+2$
and we ended with the openform exact accumulation function $f(x)=\int_a^x
(2t+2)dt$. In Equation 6.2.1 we started with the exact accumulation function
f defined as $f(x)=(x+1)^2$ and we ended with the exact rate of
change function $r_f$ defined as $r_f(x)=2x+2$. We came full circle!
$\int_a^x (2t+2)dt$ is somehow the same as $(x+1)^2$ !! That is, by finding
the exact rate of change function for $f(x)=(x+1)^2$ in closed form, we
learned about the closedform representation of that rate of change
function’s accumulation function!
Is it true that f is a
closedform representation of $r_f$’s exact accumulation function
whenever we start with an exact accumulation function f
represented in closed form and end with the exact rate of change
function $r_f$ in closed form?
Well, the general statement above is almost true.
From Exercise 6.4.2, you know that had we started with any of
$f(x)=(x+1)^2+1$, $f(x)=(x+1)^2+7.3$, or $f(x)=(x+1)^2+c$ for any constant
$c$, we would end with $r_f(x)=2x+2$ as f’s exact rate of change
function. Therefore, starting with $r_f(x)=2x+2$ does not automatically
point to $f(x)=(x+1)^2$ as the closedform representation of $\int_a^x
(2t+2)dt$. Rather, starting with $r_f(x)=2x+2$ points to a whole class of
functions that differ only by a constant, each of which has $r_f(x)=2x+2$ as
its exact rate of change function.
In Chapter 5, we always had an initial reference point at which accumulation
started. However, an exact accumulation function in closed form does not
have a natural starting point for the accumulation. We saw in section 6.1.5
that when we start with an accumulation function f and then recover
f by integrating $r_f$, we must adjust the integral by adding $f(a)$
to the integral in order to recover f exactly, so that
$f(x)=f(a)+\int_a^x r_f(t)dt$. A little algebra then gives us $\int_a^x
r_f(t)dt=f(x)f(a)$ where f is any function
that has $r_f$ as its exact rate of change function.
The last statement bears repeating. It is so important in the historical
development of calculus that it was given a special name. It is called The
Fundamental Theorem of Calculus.
6.2.3 Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus (FTC) reveals how to compute values of
an exact accumulation from values of an exact rate of change function.
Fundamental Theorem of Calculus:
For any exact accumulation
function f that has $r_f$ as its exact rate of change
function, $$\int_a^x r_f(t)dt=f(x)f(a).$$

The importance of the FTC is this:
Every time we derive a closedform representation of an exact rate of change
function $r_f$ from a closedform representation of an exact accumulation
function f, we then know that $\int_a^x r_f(t)dt$ can be expressed
in closed form as $f(x)f(a)$.
Put another way, we can compute the value of $\int_a^x r_f(t)dt$ by
computing $f(x)f(a)$.
As a concrete example, we learned that $r_f(x)=2x+2$ when $f(x)=(x+1)^2$. By
the FTC, we now can say that $$\int_a^x (2t+2)dt = (x+1)^2(a+1)^2.$$That is
to say, we can use $(x+1)^2(a+1)^2$ to compute the value of $\int_a^x
(2t+2)dt$ for any value of x and any value of a.
Closed form representations of integrals allow us to compute integrals
directly, without having to approximate them by adding bits of accumulation.
The FTC tells us that we have actually accomplished two things whenever we
derive an exact rate of change function $r$ in closed form from an exact
accumulation function $f$ in closed form: (1) we derived f’s rate of
change function, and (2) we found a closed form representation of $\int_a^x
r_(t)dt$.
The second accomplishment motivates us to find exact rate of change
functions for as many types of accumulation functions as we can.
Finding exact rate of change functions from exact accumulation functions
will be helpful in evaluating exact values of integrals.
We shall do this in Section 6.3.
Historical Note on Derivatives and Antiderivatives
There are customary names for two functions f and $r_f$ when f
is an exact accumulation function for $r_f$ and $r_f$ is f’s exact
rate of change function.
The custom is that $r_f$ is called a derived function (or derivative)
of f and that f is called an antiderivative
of $r_f$.
We are compelled to point out, however, that being called an antiderivative
or derivative confers no additional meaning to the fact that f is an
exact accumulation function for $r_f$ and that $r_f$ is the exact rate of
change function for $f$.
Exercise Set 6.2.3
These exercises are designed to help you solidify your understanding of the
FTC.

State the FTC in your own words.

Let $r(x)=2x+2$. Use the FTC to define $F(x)=\int_{1}^x
r(t)dt$ in closed form. What is $F(10)$? What does $F(10)$ mean?

Let $r(u)=2u+2$. Use the FTC to define $G(s)=\int_{3}^s
r(t)dt$ in closed form. What is $G(1)$? What does $G(1)$ mean?

Let $r(t)=3(t1)^2$. Use the FTC to express $H(u)=\int_2^u
r(p)dp$ in closed form. What is $H(12)$? What does $H(12)$ mean?

Let $r(t)=3(t1)^2$. Use the FTC to define
$J(u)=\int_a^u r(p)dp$ in closed form and to define $I(u)=\int_u^a
r(p)dp$ in closed form. Show that $J(u) = I(u)$.
 The FTC says that $\int_a^x r_f(t)dt=f(x)f(a)$ for any
function f that has $r_f$ as its exact rate of change
function. Illustrate this statement by letting $r_f(x)=3(x1)^2$ and by
using three different definitions of f, each of which as
$r_f(x)=3(x1)^2$ as its exact rate of change function.