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As explained in Chapter 3, GC is built to create graphs. It is designed to interpret anything you type as either a definition of a mathematical term (e.g., a function) or a command to display a graph. Whenever you type a wellformed statement, other than a definition, GC will attempt to display a graph of the ordered pairs or ordered triplets that make that statement true.
We describe regions in the plane by stating conditions that points in the plane must satisfy to be considered in that region. For example, the mathematical statement $\left\{(x,y)\mid x^2+y^2\le 1\right\}$, read as "The set of all points with coordinates x and y such that ...", describes the set of points in Figure 8.2.0. GC highlighted all the points in the Cartesian plane that have coordinates x and y such that $x^2+y^2\le 1$.
Notice that in Figure 8.2.0 we typed only the condition part of the mathematical statement $\left\{(x,y)\mid x^2+y^2 \le 1\right\}$. This is because GC always interprets any nondefinitional statement involving x or y as a command to "highlight all the points (x,y) such that ...".
Statement  Meaning  Result in GC 
$x=3$  Highlight all the points in the plane with coordinates $(x,y)$ such that $x=3$  
$y=x^3$  Highlight all the points in the plane with coordinates $(x,y)$ such that $y=x^3$.  
$x=y^3$  Highlight all the points in the plane with coordinates $(x,y)$ such that $x=y^3$.  
$1\le x\le 2$  Highlight all the points in the plane with coordinates $(x,y)$ such that $1\le x \le 2$.  
$1\le x \le 2, 0.5\le y \le 0$  Highlight all the points in the plane with coordinates $(x,y)$ such that $1\le x \le 2$ AND $0.5\le y \le 0$.  
$f(x)=x^2$ $g(x)=\sqrt{x}$ $y=f(x)$ $y=g(x)$ $f(x)<y<g(x)$ 
Define the functions $f$ and $g$. Highlight all the points in the plane with coordinates $(x,y)$ such that $y=f(x)$. Highlight all the points in the plane with coordinates $(x,y)$ such that $y=g(x)$. Highlight all the points in the plane with coordinates $(x,y)$ such that $f(x)\lt y$ and $y\lt g(x)$. 

$f(x)=x^2$ $g(x)=x^3$ $x=f(y)$ $x=g(y)$ $f(y)<x<g(y)$ 
Define the functions $f$ and $g$. Highlight all the points in the plane with coordinates $(x,y)$ such that $x=f(y)$. Highlight all the points in the plane with coordinates $(x,y)$ such that $x=g(y)$. Highlight all the points in the plane with coordinates $(x,y)$ such that $f(y)\lt x$ and $x\lt g(y)$. 
The quest to compute areas of regions played a large part in the early development of calculus. Indeed, many textbooks define the definite integral from a to b of a function f as the area of the region bounded by $f's$ graph, the xaxis, and the lines $x=a$ and $x=b$ (see Figure 8.2.1).
A problem with thinking of integrals as areas of regions bounded by curves is that the common notion of area is that it is always positive. However, the integral in Figure 8.2.2 is negative over the interval from 2 to 3, so for integrals to be areas a region below the xaxis must have a "negative" area (Figure 8.2.2).
In this textbook we have always spoken of integrals as accumulations of some quantity that accumulates at some rate of change. We avoided speaking of integrals as areas. But this does not mean that the two ideas (integrals as accumulations or as areas) are incompatible. In this section we will explain how they are indeed compatible. But we must look closely at the idea of signed area and its rate of change.
Examine the rectangle in Figure 8.2.3. It shows a region bounded by a rectangle that is 5 cm high and 10 cm wide. We can think of the region bounded by the rectangle as filling from left to right as the region's width varies from 0 cm to 10 cm. Since the area varies with width, we can ask about the area's rate of change with respect to changes in its width.
What is the rate of change of the enclosed region's area with respect to changes in its width? Let $w$ be the enclosed region's width as it varies. Then the value of $w$ varies from 0 to 10.
The highlighted region varies as $w$ varies, and therefore the highlighted region's area is a function of $w$, or $A(w)=5w$. To ask about the highlighted region's rate of change of area with respect to width is to ask about $r_A$, the exact rate of change function for $A$.
The rate of change of $A$ at a moment of $w$ over an interval of length $h$ is
$$(*)\qquad \begin{align} r(w)&=\frac{A(w+h)A(w)}{h}\\[1ex]
&=\frac{5(w+h)5w}{h}\\[1ex]
&=\frac{5w+5h5w}{h}\\[1ex]
&=5 \quad \mathrm{cm^2/cm} \end{align}$$
The rate of change of the rectangle's enclosed area with respect to $w$ as $w$ varies from $w=0$ to $w=10$ is 5 $\mathrm{cm^2/cm}$. That is, the numeric value of the rectangle's height is the numeric value of the area's rate of change.
Notice that we said that the numeric value of the rectangle's height is the numeric value of the area's rate of change. The rectangle's height is not the area's rate of change. The rectangle's height is 5 cm. The area's rate of change is 5 $\mathrm{cm^2/cm}$!
There was nothing special about a height of 5 cm in equation (*) above. A height of $H$ would have given us that the region's area changes with respect to width at a rate of $H \, \mathrm{ cm^2/cm}$. Indeed, a height of $f(w)$ would have given us that the region's area changes with respect to width at a rate of $f(w) \, \mathrm{ cm^2/cm}$.
To understand that a region bounded by a function's graph can have positive or negative signed area we must first be clear that function's values have directions.
Figure 8.2.3a illustrates two ways of thinking about function's values.
The first way to think about a function's values is ambiguous about how to conceive of the function's value on the graph. It is unclear whether:
The second way clarifies the matter:
How to see a value of f(x)
Reflection 8.2.1. How do you anticipate that using an arrow (vector) in Figure 8.2.3a will clarify the idea of signed (negative or positive) area? What understanding does an arrow provide that a bare line segment (as in Part 1 of Figure 8.2.3a) hides?
It would be understandable for you to wonder what this discussion about function's values has to do with areas of regions bounded by function's graphs. We hope that Figure 8.2.4 will help you make the connection.
In Figure 8.2.4, we intend that you see the region bounded by $y=0$, $x=3$, $x=3$, and $y=2\sin(x)$ being swept out as $x$ varies from 3 to 3. Upon zooming in, however, you see that the region is actually made of (potentially) infinitesimallywide rectangles, and that it is the rectangles being filled that fills the bounded region.
Each rectangle has a height of f(x), and is filled
over an interval of length $\Delta x$ as $dx$ varies through it. Each rectangle is therefore being
filled at a rate of f(x) $\mathrm{units^2/unit}$ throughout
intervals of length $\Delta x$. 
Figure 8.2.4. You can think of a region bounded by the graph of a
function as composed of rectangles of infinitesimal width. The signed
area of each rectangle changes at the rate of f(x) $units^2$ of signed area per
unit of width.
Reflection 8.2.2. Explain how a
negative value of a function produces a negative change in accumulated
signed area bounded by its graph. Explain the same for positive values
of a function producing positive changes in accumulated signed area
bounded by the function's graph.
We can now relate integrals as signed areas of bounded regions and integrals as net accumulation from rate of change.
Let f be a function whose graph is given within the Cartesian coordinate system.
Let A be the function such that $A(x)$ is the net signed area bounded by the graph of f over the interval $[a,x]$.
Each value of $f$ is the exact rate of change function for the signed area function $A$, or $f(x)=r_A(x)$. Therefore, $A(x)$, the net signed area of the region bounded by the graph of $f$ over the interval $[a,x]$, is the net accumulation of signed area that accumulates at the rate of change of $f(t)$ over intervals of length $dt$ as $t$ varies from $t=a$ to $t=x$. We say this symbolically as:
$$\begin{align}
A(x)&=\int_a^xr_A(t)dt\\[1ex]
&=\int_a^x f(t)dt\end{align}$$
A region in Cartesian space bounded by the graph of a function is just a set of points. As a region, it is neither positive nor negative. But area is a measure of a region. You will see that signed area of a region can be positive or negative depending on how the region is swept out.
A region bounded by a graph is created by a function's value sweeping along the independent axis. Function's values can be positive or negative. The animation in Figure 8.2.5 illustrates this idea.
Watch the animation, then read the narrative, then watch the
animation again, stopping it to read the narrative.
How to think of positive and negative signed area
The animation in Figure 8.2.5 gave away the computation of the signed area of a bounded region. You compute total signed area by accumulating bits of signed area that each accumulate at a rate of change of change. We know very well by now that we use an integral to do this.
Define a function A whose values $A(x)$ give the net signed area of the region bounded by $y=0$ and $g(t)=e^{\sin\left(t^{\cos t}\right)}1.5$ from $t=0$ to $t=x$ for all values of $x>0$. Display $A's$ graph in GC's right pane by entering $y'=A(x')$.
For Part 1, we must describe the regions bounded below and above the xaxis separately. Mathematically, the region above the xaxis and bounded by the graph of g is $\left\{(x,y)  x\ge 0, 0\le y\le g(x)\right\}$. The region below the xaxis and bounded by the graph of g is described mathematically as $\left\{(x,y)  x\ge 0, g(x)\le y\le 0\right\}$.
Figure 8.2.6 shows these commands and the resulting graphs in GC. In GC we need only state the conditions of the mathematical statements because GC interprets all nondefinitional commands as saying, "Graph all points $(x,y)$ such that ...".
For Part 2, we need only define the integral function as shown in Figure 8.2.7.
Figure 8.2.7. (Left) Graph of bounded region; (Right) Graph of
accumulation function, y=A(x).
Reflection 8.2.3. Examine each statement in the left margin of Figure 8.2.7. What does each statement do in regard to generating the graphs and highlighted regions in the two graphing panes?
Reflection 8.2.4. Examine the two graphs in Figure 8.2.7. Explain how the left graph and the right graph show the same thing in regard to accumulation of displacement in relation to number of seconds elapsed.
It is important to notice that the quantity represented by signed area in the left graph of Figure 8.2.7 does not have $\mathrm{meter^2}$ as its unit. Rather, it has meter as its unit. Each incremental change in signed area is created by something moving at a velocity in meters/sec for a number of seconds!
This is one of the ways that thinking about integrals as signed areas ends up being misleading. Area is measured in square units, whereas signed area (coming from an integral) has a unit that derives from the quantities involved. You avoid this confusion when you understand integrals as accumulations.
Integrals give net signed area of regions bounded by functions' graphs. Negative signed areas and positive signed areas cancel each other to varying extents. The absolute value of a function makes all values positive, as shown in Figure 8.2.8. The absolute value function makes all regions have positive signed area.
Reflection 8.2.5. The last three statements in GC produce colored regions in the displayed graphs. What regions does each statement highlight, and why does the statement highlight these regions?
Unsigned area is always positive, while signed area can be either negative or positive. Therefore an integral function that gives signed area can be increasing or decreasing over different intervals, whereas an integral function that gives unsigned area is always increasing (Figure 8.2.9).
Figure 8.2.9. Graph of $y=A(x)$ (left), the signed area function,
compared to graph of $y=\leftA(x)\right$ (right).
Connect the graphs on the left sides of Figures 8.2.8 and 8.2.9 and the
graphs on the right side of the same figures.
Figure 8.2.10 shows that the idea of signed area of regions bounded between functions' graphs is not as straightforward as the idea of the signed area of a region bounded by a functions graph and $y=0$ over an interval of $x$. The question is when to consider a region as having positive signed area and when to consider it as having negative signed area.
Reflection 8.2.6.Reset the animation in Figure 8.2.11 to its beginning after watching it once. Imagine the arrow that shows $g(x)f(x)$ in the left pane varying as the value of x varies. Then envision what will appear in the right panehow the arrow on the left will show the value of $g(x)f(x)$ in the right pane as the value of x varies. Run the animation again to confirm what you envisioned.
Reflection 8.2.7. Reset the animation in Figure 8.2.12 to its beginning after watching it once. Imagine the arrow that shows $f(x)g(x)$ in the left pane varying as the value of x varies. Then envision what will appear in the right panehow the arrow on the left will show the value of $f(x)g(x)$ in the right pane as the value of x varies. Run the animation again to confirm what you envisioned.
Figures 8.2.11 and 8.2.12 suggest that when given graphs of functions $f$ and $g$, the key to thinking about the sign of area for regions bounded between them is to decide how you are tracking them: Are you tracking how much $f(x)$ exceeds $g(x)$ or how much $g(x)$ exceeds $f(x)$?.
Figures 8.2.13 and 8.2.14 illustrate the relationship between direction of comparison between two functions and the signed area of regions bounded by their graphs.
Reflection 8.2.8. Examine the shaded regions in left and right parts of Figure 8.2.13. Must a shaded region on the left have the same signed area as the corresponding shaded region on the right? Explain.
Reflection 8.2.9. Examine the shaded regions in left and right parts of Figure 8.2.14. Must a shaded region on the left have the same signed area as the corresponding shaded region on the right? Explain.
In this entire section we have shown that the idea of integral as signed area of a region bounded by one or more graphs is entirely consistent with the general theme of this bookthat an integral is an accumulation of changes in a measured quantity that varies at a rate of change with respect to another quantity.
Moreover, we demonstrated that the general idea of integral as accumulation is coherent with signed areas of regions bounded by graphs regardless of the coordinate system.
As is always the case with integrals as accumulations, the key to integrals as signed areas in any coordinate system is to determine the appropriate rate of change function whose values give the rate of change of signed area at every moment of its independent variable.
a.  
b.  
c.  
d.  
e. 
The function $f$ gives Stefan's displacement, in miles, to the North of his house $x$ hours since he started walking. The function $r_f$ defined as $r_f(x)=\sin(5x)\dfrac{x}{2.5}$ is the exact rate of change function for $f$ with respect to $x$.
For each of a.  d., explain the meaning in this situation of the given statement. Your answer should explain both the sign and the magnitude of the expression's value if one is given.Explain the general meaning of $r_f(x)$ in regard to Stefan's displacement.
Explain the meaning of $r_f(0.4)=0.749$ in regard to Stefan's displacement.
Explain the meaning of $r_f(1.8)=0.251$ in regard to Stefan's displacement.
Explain the meaning of $f(0.4)=0.251$ in regard to Stefan's displacement.
Label the vertical axis in the right coordinate system with an appropriate unit.
The left graph shows regions colored in green and and regions colored in gray. What is the meaning (including units) of the signed areas of these regions in regard to Stefan's displacement?
The left graph shows a region colored in black from x=2.2 to x=2.5. What is the meaning (including units) of the signed area of this region in regard to Stefan's displacement?
Use GC to find the signed area of the black region. What does this number mean in regard to Stefan's displacement?
Represent your answer to part (e) by drawing something on the graph of $y=f(x)$. What you draw should reflect both sign and magnitude. Explain why you drew it as you did.
What does $f(x)g(x)$ represent in regard to this situation?
What does $g(x)f(x)$ represent in regard to this situation?
$f(x)=\mathrm{sin}(3x)$ and $g(x)=0.5\mathrm{cos}(3.5x)$. Use GC to calculate $\int_{2}^{1} (f(x)g(x))dx$.
What is the meaning (including sign and magnitude) of your answer to part (c) in regard to this situation?
Use GC to calculate $\int_{2}^{1} (g(x)f(x))dx$.
What is the meaning (including sign and magnitude) of your answer to part (e) in regard to this situation?